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1 初探重构

相似的代码我们可以用宏来简化。

2 JSON数字语法

number = [ "-" ] int [ frac ] [ exp ]
int = "0" / digit1-9 *digit
frac = "." 1*digit
exp = ("e" / "E") ["-" / "+"] 1*digit

3 数字表示方式

为简单起见，leptjson采用双精度来存储JSON数字。

4 单元测试

测试合法的数字

#define TEST_NUMBER(expect, json)\
    do {\
        lept_value v;\
        EXPECT_EQ_INT(LEPT_PARSE_OK, lept_parse(&v, json));\
        EXPECT_EQ_INT(LEPT_NUMBER, lept_get_type(&v));\
        EXPECT_EQ_DOUBLE(expect, lept_get_number(&v));\
    } while(0)

static void test_parse_number() {
    TEST_NUMBER(0.0, "0");
    TEST_NUMBER(0.0, "-0");
    TEST_NUMBER(0.0, "-0.0");
    TEST_NUMBER(1.0, "1");
    TEST_NUMBER(-1.0, "-1");
    TEST_NUMBER(1.5, "1.5");
    TEST_NUMBER(-1.5, "-1.5");
    TEST_NUMBER(3.1416, "3.1416");
    TEST_NUMBER(1E10, "1E10");
    TEST_NUMBER(1e10, "1e10");
    TEST_NUMBER(1E+10, "1E+10");
    TEST_NUMBER(1E-10, "1E-10");
    TEST_NUMBER(-1E10, "-1E10");
    TEST_NUMBER(-1e10, "-1e10");
    TEST_NUMBER(-1E+10, "-1E+10");
    TEST_NUMBER(-1E-10, "-1E-10");
    TEST_NUMBER(1.234E+10, "1.234E+10");
    TEST_NUMBER(1.234E-10, "1.234E-10");
    TEST_NUMBER(0.0, "1e-10000"); /* must underflow */
}

测试不合法用例

static void test_parse_invalid_value() {
    /* ... */
    /* invalid number */
    TEST_ERROR(LEPT_PARSE_INVALID_VALUE, "+0");
    TEST_ERROR(LEPT_PARSE_INVALID_VALUE, "+1");
    TEST_ERROR(LEPT_PARSE_INVALID_VALUE, ".123"); /* at least one digit before '.' */
    TEST_ERROR(LEPT_PARSE_INVALID_VALUE, "1.");   /* at least one digit after '.' */
    TEST_ERROR(LEPT_PARSE_INVALID_VALUE, "INF");
    TEST_ERROR(LEPT_PARSE_INVALID_VALUE, "inf");
    TEST_ERROR(LEPT_PARSE_INVALID_VALUE, "NAN");
    TEST_ERROR(LEPT_PARSE_INVALID_VALUE, "nan");
}