From 03f4d419cc4793e3593355afc04d1508a5bc2db8 Mon Sep 17 00:00:00 2001 From: =?UTF-8?q?=E2=80=9C=5Bgithub=5D=E2=80=9D?= Date: Sun, 1 Feb 2026 18:56:44 +0530 Subject: [PATCH] add Subarray Sum Equals K using prefix sum --- .../prefixsum/SubarraySumEqualsK.java | 72 +++++++++++++++++++ .../prefixsum/SubarraySumEqualskTest.java | 59 +++++++++++++++ 2 files changed, 131 insertions(+) create mode 100644 src/main/java/com/thealgorithms/prefixsum/SubarraySumEqualsK.java create mode 100644 src/test/java/com/thealgorithms/prefixsum/SubarraySumEqualskTest.java diff --git a/src/main/java/com/thealgorithms/prefixsum/SubarraySumEqualsK.java b/src/main/java/com/thealgorithms/prefixsum/SubarraySumEqualsK.java new file mode 100644 index 000000000000..d6a6bbc01663 --- /dev/null +++ b/src/main/java/com/thealgorithms/prefixsum/SubarraySumEqualsK.java @@ -0,0 +1,72 @@ +package com.thealgorithms.prefixsum; + +import java.util.HashMap; +import java.util.Map; + +/** + * Implements an algorithm to count the number of continuous subarrays + * whose sum equals a given value k. + * + *

+ * This algorithm uses the Prefix Sum technique combined with a HashMap + * to achieve O(N) time complexity. + *

+ * + *

+ * Let prefixSum[i] be the sum of elements from index 0 to i. + * A subarray (j + 1) to i has sum k if: + * + *

+ * prefixSum[i] - prefixSum[j] = k
+ * 
+ *

+ * + *

+ * The HashMap stores the frequency of each prefix sum encountered so far. + *

+ * + *

+ * Time Complexity: O(N)
+ * Space Complexity: O(N) + *

+ * + * @see Prefix Sum (Wikipedia) + * @author Ruturaj Jadhav, ruturajjadhav07 + */ +public final class SubarraySumEqualsK { + + private SubarraySumEqualsK() { + // Utility class; prevent instantiation + } + + /** + * Counts the number of subarrays whose sum equals k. + * + * @param nums The input integer array. + * @param k The target sum. + * @return The number of continuous subarrays summing to k. + * @throws IllegalArgumentException if nums is null. + */ + public static int countSubarrays(int[] nums, int k) { + if (nums == null) { + throw new IllegalArgumentException("Input array cannot be null"); + } + + Map prefixSumFrequency = new HashMap<>(); + prefixSumFrequency.put(0L, 1); + + long prefixSum = 0; + int count = 0; + + for (int num : nums) { + prefixSum += num; + + long requiredSum = prefixSum - k; + count += prefixSumFrequency.getOrDefault(requiredSum, 0); + + prefixSumFrequency.put(prefixSum, prefixSumFrequency.getOrDefault(prefixSum, 0) + 1); + } + + return count; + } +} diff --git a/src/test/java/com/thealgorithms/prefixsum/SubarraySumEqualskTest.java b/src/test/java/com/thealgorithms/prefixsum/SubarraySumEqualskTest.java new file mode 100644 index 000000000000..68f85b713046 --- /dev/null +++ b/src/test/java/com/thealgorithms/prefixsum/SubarraySumEqualskTest.java @@ -0,0 +1,59 @@ +package com.thealgorithms.prefixsum; + +import static org.junit.jupiter.api.Assertions.assertEquals; +import static org.junit.jupiter.api.Assertions.assertThrows; + +import org.junit.jupiter.api.Test; + +/** + * Tests for {@link SubarraySumEqualsK}. + */ +class SubarraySumEqualsKTest { + + @Test + void testBasicExample() { + int[] nums = {1, 1, 1}; + int k = 2; + assertEquals(2, SubarraySumEqualsK.countSubarrays(nums, k)); + } + + @Test + void testWithNegativeNumbers() { + int[] nums = {1, -1, 0}; + int k = 0; + assertEquals(3, SubarraySumEqualsK.countSubarrays(nums, k)); + } + + @Test + void testSingleElementEqualToK() { + int[] nums = {5}; + int k = 5; + assertEquals(1, SubarraySumEqualsK.countSubarrays(nums, k)); + } + + @Test + void testSingleElementNotEqualToK() { + int[] nums = {5}; + int k = 3; + assertEquals(0, SubarraySumEqualsK.countSubarrays(nums, k)); + } + + @Test + void testAllZeros() { + int[] nums = {0, 0, 0}; + int k = 0; + assertEquals(6, SubarraySumEqualsK.countSubarrays(nums, k)); + } + + @Test + void testEmptyArray() { + int[] nums = {}; + int k = 0; + assertEquals(0, SubarraySumEqualsK.countSubarrays(nums, k)); + } + + @Test + void testNullArrayThrowsException() { + assertThrows(IllegalArgumentException.class, () -> SubarraySumEqualsK.countSubarrays(null, 0)); + } +}