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string scramble.cpp
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133 lines (116 loc) · 3.22 KB
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/* http://leetcode.com/onlinejudge#question_87
http://blog.theliuy.com/scramble-string/ */
#include<iostream>
#include<math.h>
#include<time.h>
#include<vector>
using namespace std;
bool isScrambled(string &s1, string &s2)
{
int len = s1.length();
if (len != s2.length()) return false;
if (s1.compare(s2) == 0) return true;
unsigned int scode1 = 0;
unsigned int scode2 = 0;
for (int i = 0; i< len; ++i)
{
scode1 += s1[i];
scode2 += s2[i];
}
if (scode1 != scode2) return false;
for(int i = 1; i < len; ++i)
{
if (isScrambled(s1.substr(0,i), s2.substr(0,i)) && isScrambled(s1.substr(i, s1.length() - i), s2.substr(i, s2.length()-i))
|| isScrambled(s1.substr(0,i), s2.substr(s2.length() - i,i))
&& isScrambled(s1.substr(i,s1.length()-i), s2.substr(0,s2.length()-i)))
return true;
}
return false;
}
bool isScrambledEx(string &s1, string &s2)
{
if (s1.length() == 0 || s2.length() == 0)
return false;
int i = 0;
int j = s1.length() - 1;
if (s1.compare(s2) == 0)
{
return true;
}
else
{
if (s1.length() > 1)
{
if (isScrambledEx(s1.substr(0, i + 1), s2.substr(j - i, j))
&& isScrambledEx(s1.substr(i + 1, j), s2.substr(0, j - i)))
return true;
if(isScrambledEx(s1.substr(0, j - i), s2.substr(i + 1, j))
&& isScrambledEx(s1.substr(j - i, j), s2.substr(0, i + 1)))
return true;
if (isScrambledEx(s1.substr(0, i + 1), s2.substr(0, i + 1))
&& isScrambledEx(s1.substr(i + 1, j), s2.substr(i + 1, j)))
return true;
if (isScrambledEx(s1.substr(0, j - i), s2.substr(0, j - i))
&& isScrambledEx(s1.substr(j - i, j), s2.substr(j - i, j)))
return true;
if (isScrambledEx(s1.substr(0, (i + j)/2 + 1), s2.substr(0, (i + j)/2 + 1))
&& isScrambledEx(s1.substr((i + j)/2 + 1, j), s2.substr((i + j)/2 + 1, j)))
return true;
if (isScrambledEx(s1.substr(0, (i + j)/2 ), s2.substr(0, (i + j)/2))
&& isScrambledEx(s1.substr((i + j)/2, j), s2.substr((i + j)/2, j)))
return true;
return false;
}
else
return false;
}
}
// dynamic programming.
// assume i -- the start index on s1, j -- the start index on s2, p -- the size of string.
// state function f(i, j, k) = true if for any n = 1...k-1,
// f(i, j + n, k - n) == true && f(i + k - n, j, n) == true
// or f(i, j, n) == true && f(i + n, j + n, k - n) == true;
bool isScrambleDP(string s1, string s2) {
int n = s1.size();
vector<vector<vector<int>>> m(n + 1, vector<vector<int>>(n + 1, vector<int>(n + 1, 0)));
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
m[i][j][1] = (s1[i] == s2[j]);
}
}
for (int p = 2; p <= n; p++) {
for (int i = 0; i <= n - p; i++) {
for (int j = 0; j <= n - p; j++) {
for (int k = 1; k <= p - 1; k++) {
if (m[i][j][k] && m[i + k][j + k][p - k]) {
m[i][j][p] = 1;
break;
} else if (m[i][j+k][p-k] && m[i + p - k][j][k]) {
m[i][j][p] = 1;
break;
}
}
}
}
}
return m[0][0][s1.size()];
}
int main()
{
string s1 = "abcd";//"abbbcbaaccacaacc";
string s2 = "badc";//"acaaaccabcabcbcb";//"badc"; "dbac"
__time32_t start, end;
_time32(&start);
if (isScrambleDP(s1, s2))
{
cout<<"TRUE";
}
else
{
cout<<"FALSE";
}
_time32(&end);
cout<<endl<<_difftime32(end, start);
getchar();
return 0;
}