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IslandPerimeter.java
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59 lines (55 loc) · 1.64 KB
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package easy;
/**
* ClassName: IslandPerimeter.java
* Author: chenyiAlone
* Create Time: 2019/9/11 22:02
* Description: No.463 Island Perimeter
* 思路:
*
* 统计当前的陆地相邻的海的个数即可
*
*
* You are given a map in form of a two-dimensional integer grid where 1 represents land and 0 represents water.
*
* Grid cells are connected horizontally/vertically (not diagonally). The grid is completely surrounded by water, and there is exactly one island (i.e., one or more connected land cells).
*
* The island doesn't have "lakes" (water inside that isn't connected to the water around the island). One cell is a square with side length 1. The grid is rectangular, width and height don't exceed 100. Determine the perimeter of the island.
*
*
*
* Example:
*
* Input:
* [[0,1,0,0],
* [1,1,1,0],
* [0,1,0,0],
* [1,1,0,0]]
*
* Output: 16
*
*
*/
public class IslandPerimeter {
private int[] dx = {0, 1, 0, -1};
private int[] dy = {1, 0, -1, 0};
private int count(int[][] grid, int x, int y) {
int m = grid.length, n = grid[0].length;
int ret = 0;
for (int i = 0; i < 4; i++) {
int nx = x + dx[i], ny = y + dy[i];
if (0 <= nx && nx < m && 0 <= ny && ny < n && grid[nx][ny] == 1) continue;
ret++;
}
return ret;
}
public int islandPerimeter(int[][] grid) {
int m = grid.length, n = grid[0].length, ret = 0;
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
if (grid[i][j] == 1)
ret += count(grid, i, j);
}
}
return ret;
}
}