-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathLRUCache.java
More file actions
141 lines (120 loc) · 3.91 KB
/
LRUCache.java
File metadata and controls
141 lines (120 loc) · 3.91 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
package hard;
import java.util.HashMap;
import java.util.Map;
/**
*
* ClassName: LRUCache
* @author chenyiAlone
* Create Time: 2019/04/26 12:50:39
* Description: No.146
* 思路:
* 1. Deque + HashMap
* 2. class Node {
* int key;
* int val;
* Node pre;
* Node next;
* }
* 3. 需要注意的地方就是到达 capacity 的时候,将尾部元素删除,cur 总是插入到 head 的 next 位置
*
* Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and put.
get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.
put(key, value) - Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.
Follow up:
Could you do both operations in O(1) time complexity?
Example:
LRUCache cache = new LRUCache(2); // capacity
cache.put(1, 1);
cache.put(2, 2);
cache.get(1); // returns 1
cache.put(3, 3); // evicts key 2
cache.get(2); // returns -1 (not found)
cache.put(4, 4); // evicts key 1
cache.get(1); // returns -1 (not found)
cache.get(3); // returns 3
cache.get(4); // returns 4
*
*/
public class LRUCache {
private class Node {
Node pre;
Node next;
int val;
int key;
public Node() {}
public Node(int val, int key) {
this.val = val;
this.key = key;
}
}
int capac = 0;
int len = 0;
Node head = null;
Node tail = null;
Map<Integer, Node> map = new HashMap<>();
public LRUCache(int capacity) {
head = new Node();
tail = new Node();
head.next = tail;
tail.pre = head;
this.capac = capacity;
}
public int get(int key) {
int res = -1;
if (map.containsKey(key)) {
Node cur = map.get(key);
res = cur.val;
Node pre = cur.pre;
Node next = cur.next;
pre.next = next;
next.pre = pre;
head.next.pre = cur;
cur.next = head.next;
head.next = cur;
cur.pre = head;
}
return res;
}
public void put(int key, int value) {
Node cur = null;
if (map.containsKey(key)) {
cur = map.get(key);
// cut cur form list
Node pre = cur.pre;
Node next = cur.next;
pre.next = next;
next.pre = pre;
// set value to new value
cur.val = value;
// insert into list after head
head.next.pre = cur;
cur.next = head.next;
head.next = cur;
cur.pre = head;
} else {
cur = new Node(value, key);
if (capac > len) {
len++;
map.put(key, cur);
} else {
// remove last
Node last = tail.pre;
last.pre.next = last.next;
last.next.pre = last.pre;
map.remove(last.key);
}
// insert into list after head
head.next.pre = cur;
cur.next = head.next;
head.next = cur;
cur.pre = head;
}
map.put(key, cur);
}
}
/**
* Your LRUCache object will be instantiated and called as such:
* LRUCache obj = new LRUCache(capacity);
* int param_1 = obj.get(key);
* obj.put(key,value);
*/