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LongestPalindromicSubstring.java
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87 lines (83 loc) · 2.98 KB
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package hard;
/**
* Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000.
* Example 1:
* Input: "babad"
* Output: "bab"
* Note: "aba" is also a valid answer.
*
* Example 2:
* Input: "cbbd"
* Output: "bb"
*
* @author chenyiAlone
*
*/
public class LongestPalindromicSubstring {
public String longestPalindrome(String s) {
int size = 0;
int start = -1;
int lo, hi;
boolean flag = true;
for (int i = 0; i < s.length(); i++) {
for (int j = 0; j + i < s.length(); j++) {
lo = i;
hi = i + j;
// System.out.println("lo = " + lo + " hi = " + hi);
while (lo <= hi) {
if (s.charAt(lo) != s.charAt(hi)) { // 两侧向中间依次进行比较
flag = false;
break;
}
lo++;
hi--;
}
// System.out.println("sub = " + s.substring(i, i + j + 1) + " is " + flag);
if (flag && size < j + 1) {
size = j + 1;
start = i;
}
flag = true;
}
}
if (start != -1) return s.substring(start, start + size);
return "";
}
/**
* 第一个使用了StringBuffer来判断是否是回文的版本,
* 但是对于长的字符串s操作超时,失败
* @param s
* @return
*/
public String longestPalindromeA(String s) {
int size = 0;
int start = -1;
for (int i = 0; i < s.length(); i++) {
for (int j = 1; j + i <= s.length(); j++) {
String sub = s.substring(i, i + j);
boolean flag = sub.equals(new StringBuffer(sub).reverse().toString()) && j > size;
if (flag) {
size = j;
start = i;
}
// System.out.println(sub + " is flag = " + flag);
}
}
// System.out.println("start = " + start + " size = " + size);
if (start != -1) return s.substring(start, start + size);
return "";
}
public static boolean isPalind(String s, int start, int size) {
String sub = s.substring(start, start + size);
if (sub.equals("")) return false;
// System.out.println(sub + " is " + sub.equals(new StringBuffer(sub).reverse().toString()));
return sub.equals(new StringBuffer(sub).reverse().toString());
}
public static void main(String[] args) {
String s = "bab";
LongestPalindromicSubstring ls = new LongestPalindromicSubstring();
System.out.println("ans = " + ls.longestPalindrome(s));
// System.out.println("s".charAt(0));
// System.out.println("abcd".substring(0, 0 + 3));
}
}