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LinkedListRandomNode.java
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67 lines (62 loc) · 1.8 KB
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package medium;
import util.ListNode;
import java.util.Random;
/**
* ClassName: LinkedListRandomNode.java
* Author: chenyiAlone
* Create Time: 2019/7/25 21:41
* Description: No.382 Linked List Random Node
* 思路:
*
* 1 2 3 4 5 ... n
* 1/1 1/2 1/3 1/4 1/5 ... 1/n
*
*
*
* Given a singly linked list, return a random node's value from the linked list. Each node must have the same probability of being chosen.
*
* Follow up:
* What if the linked list is extremely large and its length is unknown to you? Could you solve this efficiently without using extra space?
*
* Example:
*
* // Init a singly linked list [1,2,3].
* ListNode head = new ListNode(1);
* head.next = new ListNode(2);
* head.next.next = new ListNode(3);
* Solution solution = new Solution(head);
*
* // getRandom() should return either 1, 2, or 3 randomly. Each element should have equal probability of returning.
* solution.getRandom();
*
*/
public class LinkedListRandomNode {
private ListNode list;
private Random random;
/** @param head The linked list's head.
Note that the head is guaranteed to be not null, so it contains at least one node. */
public LinkedListRandomNode(ListNode head) {
this.list = head;
this.random = new Random();
}
/** Returns a random node's value. */
public int getRandom() {
ListNode cur = list;
int ret = 0;
int cnt = 1;
// random() * 3 < 1
while (cur != null) {
if (cnt * random.nextDouble() < 1) {
ret = cur.val;
}
cur = cur.next;
cnt++;
}
return ret;
}
}
/**
* Your Solution object will be instantiated and called as such:
* Solution obj = new Solution(head);
* int param_1 = obj.getRandom();
*/