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LongestSubstringWithoutRepeatingCharacters.java
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58 lines (55 loc) · 1.66 KB
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package medium;
/**
* Given a string, find the length of the longest substring without repeating characters.
* Example 1:
* Input: "abcabcbb"
* Output: 3
* Explanation: The answer is "abc", with the length of 3.
*
* Example 2:
* Input: "bbbbb"
* Output: 1
* Explanation: The answer is "b", with the length of 1.
*
* Example 3:
* Input: "pwwkew"
* Output: 3
* Explanation: The answer is "wke", with the length of 3.
Note that the answer must be a substring,
"pwke" is a subsequence and not a substring.
* @author chenyiAlone
*
*/
public class LongestSubstringWithoutRepeatingCharacters {
/**
* arr map
*/
public int lengthOfLongestSubstring2(String s) {
int[] map = new int[256];
int ret = 0;
for (int i = 0, j = 0; i < s.length(); i++) {
j = Math.max(j, map[s.charAt(i)]);
ret = Math.max(ret, i - j + 1);
map[s.charAt(i)] = i + 1;
}
return ret;
}
public int lengthOfLongestSubstring(String s) {
if (s.length() == 1) return 1;
int max = 0;
for (int lo = 0, i = 0; i < s.length(); i++) {
int x = lastEqualIndex(s, lo, i);
if (i- x > max) max = i - x;
lo = x + 1;
}
return max;
}
// 放回扫描元素之前的元素中与他相同的第一个元素的下标
public static int lastEqualIndex(String str,int lo, int x) {
char c = str.charAt(x);
while (x-- > lo) {
if (str.charAt(x) == c) return x;
}
return x;
}
}