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WiggleSubsequence.java
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62 lines (61 loc) · 2.15 KB
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package medium;
/**
* ClassName: WiggleSubsequence.java
* Author: chenyiAlone
* Create Time: 2019/5/24 13:54
* Description: No.376
* 思路:
* 1. 去重!
* 2. len < 2,return len
* 3. return 中间所有的顶点数 + 2
*
*
*
* A sequence of numbers is called a wiggle sequence if the differences between successive numbers strictly alternate between positive and negative. The first difference (if one exists) may be either positive or negative. A sequence with fewer than two elements is trivially a wiggle sequence.
*
* For example, [1,7,4,9,2,5] is a wiggle sequence because the differences (6,-3,5,-7,3) are alternately positive and negative. In contrast, [1,4,7,2,5] and [1,7,4,5,5] are not wiggle sequences, the first because its first two differences are positive and the second because its last difference is zero.
*
* Given a sequence of integers, return the length of the longest subsequence that is a wiggle sequence. A subsequence is obtained by deleting some number of elements (eventually, also zero) from the original sequence, leaving the remaining elements in their original order.
*
* Example 1:
*
* Input: [1,7,4,9,2,5]
* Output: 6
* Explanation: The entire sequence is a wiggle sequence.
* Example 2:
*
* Input: [1,17,5,10,13,15,10,5,16,8]
* Output: 7
* Explanation: There are several subsequences that achieve this length. One is [1,17,10,13,10,16,8].
* Example 3:
*
* Input: [1,2,3,4,5,6,7,8,9]
* Output: 2
* Follow up:
* Can you do it in O(n) time?
*
*/
public class WiggleSubsequence {
public int wiggleMaxLength(int[] nums) {
int[] tmp = new int[nums.length];
int p = 0;
for (int i = 0; i < nums.length; i ++) {
tmp[p] = nums[i];
p ++;
while (i < nums.length - 1 && nums[i] == nums[i + 1])
i ++;
}
nums = tmp;
if (p < 2)
return p;
int res = 2;
for (int i = 1; i < p - 1; i ++) {
int a = nums[i - 1], b = nums[i], c = nums[i + 1];
if (a < b && b > c)
res ++;
else if (a > b && b < c)
res ++;
}
return res;
}
}