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Copy path28. ReverseALinkedList.java
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28. ReverseALinkedList.java
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115 lines (98 loc) · 2.12 KB
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public class LL {
Node head;
private int size;
LL() {
this.size = 0;
}
class Node {
String data;
Node next;
Node(String data) {
this.data = data;
this.next = null;
size++;
}
}
//add first
public void addFirst(String data) {
Node newNode = new Node(data);
if(head == null) {
head = newNode;
return;
}
newNode.next = head;
head = newNode;
}
//add last
public void addLast(String data) {
Node newNode = new Node(data);
if(head == null) {
head = newNode;
return;
}
Node currNode = head;
while(currNode.next != null) {
currNode = currNode.next;
}
currNode.next = newNode;
}
//iterative method
//time complexity -> O(n)
//space complexity -> O(1)
public void reverseList() {
if(head == null || head.next == null) {
return;
}
Node prevNode = head;
Node currNode = head.next;
while(currNode != null) {
Node nextNode = currNode.next;
currNode.next = prevNode;
prevNode = currNode;
currNode = nextNode;
}
head.next = null;
head = prevNode;
}
//print
public void printList() {
if(head == null) {
System.out.println("list is empty.");
return;
}
Node currNode = head;
while(currNode != null) {
System.out.print(currNode.data + " -> ");
currNode = currNode.next;
}
System.out.println("NULL");
}
//main function
public static void main(String[] args) {
LL list = new LL();
list.addLast("1");
list.addLast("2");
list.addLast("3");
list.addLast("4");
list.printList();
list.reverseList();
list.printList();
}
}
/* you can check out the recursive method on google. let's suppose it is you home task ;) */
//collection method
//time complexity -> O(n)
//space complexity -> O(1)
import java.util.*;
public class LL {
public static void main(String[] args) {
LinkedList<Integer> list = new LinkedList<>();
list.add(1);
list.add(2);
list.add(3);
System.out.println(list);
Collections.reverse(list);
System.out.println(list);
}
}
/* BYE BYEEEEEEEE! ^_^ */