Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively.
Below is one possible representation of s1 = "great":
great
/ \
gr eat
/ \ / \
g r e at
/ \
a t
To scramble the string, we may choose any non-leaf node and swap its two children.
For example, if we choose the node "gr" and swap its two children, it produces a scrambled string "rgeat".
rgeat
/ \
rg eat
/ \ / \
r g e at
/ \
a t
We say that "rgeat" is a scrambled string of "great".
Similarly, if we continue to swap the children of nodes "eat" and "at", it produces a scrambled string "rgtae".
rgtae
/ \
rg tae
/ \ / \
r g ta e
/ \
t a
We say that "rgtae" is a scrambled string of "great".
Given two strings s1 and s2 of the same length, determine if s2 is a scrambled string of s1.
/**
* @param {string} s1
* @param {string} s2
* @return {boolean}
*/
var isScramble = function(s1, s2) {
var l1 = s1.length;
var l2 = s2.length;
if (l1 !== l2) {
return false;
}
if (l1 === 1) {
return s1 === s2;
}
var flag;
flag = s1.split('').sort().join('') === s2.split('').sort().join('');
if (!flag) {
return false;
}
flag = false;
var s11, s12, s21, s22;
for (var i = 1; i < l1 && !flag; i++) {
s11 = s1.slice(0, i);
s12 = s1.slice(i);
s21 = s2.slice(0, i);
s22 = s2.slice(i);
flag = isScramble(s11, s21) && isScramble(s12, s22);
if (!flag) {
s21 = s2.slice(l1 - i);
s22 = s2.slice(0, l1 - i);
flag = isScramble(s11, s21) && isScramble(s12, s22);
}
}
return flag;
};