Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example: Given the below binary tree and sum = 22,
5
/ \
4 8
/ / \
11 13 4
/ \ / \
7 2 5 1
return
[
[5,4,11,2],
[5,8,4,5]
]
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @param {number} sum
* @return {number[][]}
*/
var result;
var pathSum = function(root, sum) {
if (root === null) {
return [];
}
result = [];
solution(root, sum, []);
return result;
};
var solution = function (root, sum, collect) {
if (root.left === null && root.right === null) {
if (sum - root.val === 0) {
collect.push(root.val);
result.push(collect);
}
return;
}
collect.push(root.val);
if (root.left !== null) {
solution(root.left, sum - root.val, collect.slice());
}
if (root.right !== null) {
solution(root.right, sum - root.val, collect.slice());
}
};