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problem017.py
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"""
If the numbers 1 to 5 are written out in words: one, two, three, four, five,
then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.
If all the numbers from 1 to 1000 (one thousand) inclusive were written out in
words, how many letters would be used?
NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and
forty-two) contains 23 letters and 115 (one hundred and fifteen) contains
20 letters. The use of "and" when writing out numbers is in compliance with
British usage.
"""
NUMBERS = {
0: "zero",
1: "one",
2: "two",
3: "three",
4: "four",
5: "five",
6: "six",
7: "seven",
8: "eight",
9: "nine",
10: "ten",
11: "eleven",
12: "twelve",
13: "thirteen",
14: "fourteen",
15: "fifteen",
16: "sixteen",
17: "seventeen",
18: "eighteen",
19: "nineteen",
20: "twenty",
30: "thirty",
40: "forty",
50: "fifty",
60: "sixty",
70: "seventy",
80: "eighty",
90: "ninety"
}
def letters_of(number):
"""letters_of returns the amount of letters neccessary to write the given
number in english words. Tested only from 0 up to the number 9999.
>>> letters_of(0)
4
>>> letters_of(23)
11
>>> letters_of(9999)
36
"""
if number in NUMBERS:
return len(NUMBERS[number])
letters = []
if number >= 1000:
letters.append(NUMBERS[number // 1000])
letters.append("thousand")
number %= 1000
if number >= 100:
letters.append(NUMBERS[number // 100])
letters.append("hundred")
number %= 100
if number != 0:
letters.append("and")
if number >= 20:
letters.append(NUMBERS[(number // 10) * 10])
number %= 10
if number > 0:
letters.append(NUMBERS[number])
return sum(map(len, letters))
def main():
"""
>>> main()
21124
"""
print(sum(map(letters_of, xrange(1, 1001))))
if __name__ == "__main__":
import doctest
doctest.testmod()