It seems that column transformation functions defined using macros can behave differently than functions defined without macros. Here's an example:
using Match, DataFrames, Query
df = DataFrame(a = [1, 2], b = [3, missing])
f(x) = @match x begin
3 => "three"
_ => missing
end
df |>
@map({_..., c = f(_.b)}) |>
@replacena("successfully replaced")
The output still has NAs in it, despite the final @replacena command.
If I replace f with an equivalent version without macros (even just the one obtained by expanding the macro), this works as expected.
It seems that column transformation functions defined using macros can behave differently than functions defined without macros. Here's an example:
The output still has NAs in it, despite the final
@replacenacommand.If I replace
fwith an equivalent version without macros (even just the one obtained by expanding the macro), this works as expected.