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No37SerializedBinaryTree.java
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231 lines (194 loc) · 4.97 KB
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package com.wzx.sword;
import com.wzx.entity.TreeNode;
import java.util.Deque;
import java.util.LinkedList;
/**
* @author wzx
* @see <a href="https://leetcode-cn.com/problems/xu-lie-hua-er-cha-shu-lcof">https://leetcode-cn.com/problems/xu-lie-hua-er-cha-shu-lcof</a>
*/
public class No37SerializedBinaryTree {
private int offset = 0;
private String str = null;
private TreeNode getNextNode() {
String num = "";
char ch;
while ((ch = str.charAt(offset++)) != '!') {
if (ch == '#') return null;
// 可能存在许多位数为1,2的数,频繁创建StringBuilder不太好
num += ch;
}
return new TreeNode(Integer.parseInt(num));
}
/**
* 扩充二叉树层序遍历
*/
public class Codec1 {
/**
* 层序遍历
* <p>
* time: O(n)
* space: O(n)
*/
public String serialize(TreeNode root) {
Deque<TreeNode> queue = new LinkedList<>();
if (root != null) queue.add(root);
StringBuilder sb = new StringBuilder();
while (!queue.isEmpty()) {
TreeNode node = queue.pollLast();
if (node == null) {
sb.append('#');
} else {
sb.append(node.val).append('!');
queue.addFirst(node.left);
queue.addFirst(node.right);
}
}
return sb.toString();
}
/**
* 反序列化,层序遍历
* <p>
* time: O(n)
* space: O(n)
*/
public TreeNode deserialize(String data) {
if (data.isEmpty()) return null;
offset = 0;
str = data;
TreeNode root = getNextNode();
// 已反序列化的所有节点
Deque<TreeNode> queue = new LinkedList<>();
queue.add(root);
while (offset < data.length()) {
TreeNode node = queue.pollLast();
// 左子结点
TreeNode left = getNextNode();
if (left != null) {
node.left = left;
queue.addFirst(node.left);
}
// 右子结点
if (offset < data.length()) {
TreeNode right = getNextNode();
if (right != null) {
node.right = right;
queue.addFirst(node.right);
}
}
}
return root;
}
}
/**
* 扩充二叉树前序遍历
*/
public class Codec2 {
/**
* 前序遍历
* <p>
* time: 0(n)
* space: O(n)
*/
public String serialize(TreeNode root) {
if (root == null) return null;
StringBuilder sb = new StringBuilder();
recursion(root, sb);
return sb.toString();
}
private void recursion(TreeNode root, StringBuilder sb) {
if (root == null) {
sb.append('#');
return;
}
sb.append(root.val).append('!');
recursion(root.left, sb);
recursion(root.right, sb);
}
/**
* 前序遍历 = {root, left, right}
* <p>
* time: O(n)
* space: O(n)
*/
public TreeNode deserialize(String data) {
if (data == null) return null;
offset = 0;
str = data;
return recursion(data);
}
private TreeNode recursion(String str) {
if (offset >= str.length()) return null;
TreeNode node = getNextNode();
if (node != null) {
node.left = recursion(str);
node.right = recursion(str);
}
return node;
}
}
/**
* 扩充二叉树后序遍历
*/
public class Codec3 {
/**
* 后序遍历
* <p>
* time: O(n)
* space: O(n)
*/
public String serialize(TreeNode root) {
if (root == null) return null;
StringBuilder sb = new StringBuilder();
recursion(root, sb);
return sb.toString();
}
private void recursion(TreeNode root, StringBuilder sb) {
if (root == null) {
sb.append('#');
return;
}
recursion(root.left, sb);
recursion(root.right, sb);
sb.append(root.val).append('!');
}
/**
* 后序遍历 = {left, right, root}
* <p>
* time: O(n)
* space: O(n)
*/
public TreeNode deserialize(String data) {
if (data == null) return null;
offset = 0;
StringBuilder sb = new StringBuilder(data.length());
// reverse = {root, right, left}
for (int i = data.length() - 1; i >= 0; i--) {
if (data.charAt(i) == '!') {
// 翻转数字
int numStart = i;
while (numStart-- > 0) {
if (data.charAt(numStart) == '!' || data.charAt(numStart) == '#') {
numStart++;
break;
}
}
for (int j = numStart; j <= i; j++) sb.append(data.charAt(j));
i = numStart;
} else {
sb.append(data.charAt(i));
}
}
str = sb.toString();
return recursion(str);
}
private TreeNode recursion(String str) {
if (offset >= str.length()) return null;
TreeNode node = getNextNode();
if (node != null) {
node.right = recursion(str);
node.left = recursion(str);
}
return node;
}
}
}