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PalindromePartitioning.java
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50 lines (45 loc) · 1.38 KB
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/*
*Given a string s, partition s such that every substring of the partition is a palindrome.
*Return all possible palindrome partitioning of s.
*/
/*
*solution:递归实现
*/
public class Solution {
public List<List<String>> partition(String s) {
List<List<String>> list = new ArrayList<List<String>>();
if(s.length() <=0 || s==null){
return list;
}
ArrayList<String> partition = new ArrayList<String>();
addPalindrome(s,0,partition,list);
return list;
}
public void addPalindrome(String s,int start,List<String> partition,List<List<String>> result){
if(start == s.length()){
ArrayList<String> temp = new ArrayList<String>(partition);
result.add(temp);
return;
}
for(int i= start+1; i<=s.length();i++){
String str = s.substring(start,i);
if(isPalindrome(str)){
partition.add(str);
addPalindrome(s,i,partition,result);
partition.remove(partition.size()-1);
}
}
}
private boolean isPalindrome(String s){
int left = 0;
int right = s.length()-1;
while(left < right){
if(s.charAt(left) != s.charAt(right)){
return false;
}
left++;
right--;
}
return true;
}
}